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3.3 KiB
3.3 KiB
id, title, category, status, verification_status, canonical_id, aliases, duplicate_of, source_trust_level, confidence_score, created_at, updated_at, review_reason, merge_history, tags, raw_sources, applied_in, github_commit
| id | title | category | status | verification_status | canonical_id | aliases | duplicate_of | source_trust_level | confidence_score | created_at | updated_at | review_reason | merge_history | tags | raw_sources | applied_in | github_commit | |||||||
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| python-pass-statement | Python Pass Statement | Programming_Language | draft | conceptual |
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B | 0.88 | 2026-07-04 | 2026-07-04 |
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Python Pass Statement
🎯 한 줄 통찰 (One-line insight)
Python cannot have a truly empty code block — a comment alone raises an IndentationError — so pass exists as an actual (no-op) statement that satisfies the syntax requirement while doing nothing. [S1]
🧠 핵심 개념 (Core concepts)
pass— a null operation; nothing happens when it executes; a placeholder. [S1]- Why needed — if/for/function/class blocks cannot be syntactically empty in Python. [S1]
- Common uses — sketching structure before implementing logic, satisfying syntax when no action is needed, placeholders during development, empty functions/classes planned for later. [S1]
passvs. comments — a comment is ignored entirely by Python and does NOT satisfy the "block needs a statement" requirement;passdoes. [S1]- Works in other contexts too — loops, functions, classes, not just if statements. [S1]
🧩 추출된 패턴 (Extracted patterns)
- Comment-only block is a common beginner error —
if score > 90: # commentwith no actual statement raisesIndentationError, since comments aren't statements —passis the fix. [S1]
📖 세부 내용 (Details)
- Basic pass:
if b > a: pass. [S1] - Comment-only block fails:
if score > 90: # This is excellentalone raises IndentationError. [S1] - Fixed with pass:
if score > 90: pass # This is excellent. [S1] - In a function stub:
def calculate_discount(price): pass # TODO: Implement discount logic. [S1]
⚖️ 모순 및 업데이트 (Contradictions & updates)
소스에서 모순되는 정보는 발견되지 않음.
🛠️ 적용 사례 (Applied in summary)
현재 발견된 실제 적용 사례가 없습니다 — 함수/클래스의 스텁(stub) 구현에 표준적으로 쓰이는 패턴이다. [S1]
💻 코드 패턴 (Code patterns)
pass as a function stub placeholder (Python):
def calculate_discount(price):
pass # TODO: Implement discount logic
✅ 검증 상태 및 신뢰도
- 상태: draft
- 검증 단계: conceptual
- 출처 신뢰도: B (W3Schools — widely used educational reference, not a primary standards body)
- 신뢰 점수: 0.88
- 중복 검사 결과: 신규 생성 (New discovery)
🔗 지식 그래프 (Knowledge Graph)
- 상위/루트: Python Tutorial
- 관련 개념: Python If Statement, Python For Loops, Python Functions
- 참조 맥락: 빈 블록이 필요한 모든 곳(if/for/함수/클래스)에서 재사용되는 플레이스홀더.
📚 출처 (Sources)
- [S1] W3Schools — Python Pass Statement — https://www.w3schools.com/python/python_if_pass.asp
📝 변경 이력 (Change history)
- 2026-07-04: Initial draft synthesized from the W3Schools "Python Pass Statement" page (Astra wiki-curation, P-Reinforce v3.1 format).