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id title category status verification_status canonical_id aliases duplicate_of source_trust_level confidence_score created_at updated_at review_reason merge_history tags raw_sources applied_in github_commit
python-nested-if Python Nested If Programming_Language draft conceptual
Nested If Statements
파이썬 중첩 조건문
B 0.9 2026-07-04 2026-07-04
python
programming
w3schools
if
nested
https://www.w3schools.com/python/python_if_nested_if.asp

Python Nested If

🎯 한 줄 통찰 (One-line insight)

Nesting an if inside another if lets the inner condition depend on the outer one being true first, and it's interchangeable with and when both conditions are equally simple — nesting wins when the inner logic is genuinely conditional on the outer branch. [S1]

🧠 핵심 개념 (Core concepts)

  • Nested if — an if statement inside another if statement; the inner one only runs when the outer condition is true. [S1]
  • Multiple nesting levels — legal to any depth, but readability degrades quickly with too many levels. [S1]
  • Nested if vs. andif temperature > 20: if is_sunny: ... is equivalent to if temperature > 20 and is_sunny: ... when there's no independent action tied to just the outer condition. [S1]

🧩 추출된 패턴 (Extracted patterns)

  • When to nest vs. combine with and — use nested if when the inner logic is complex or genuinely depends on the outer condition (e.g. different messages at each level); use and when both conditions are simple and equally weighted. [S1]

📖 세부 내용 (Details)

  • Basic nesting: if x > 10: print("Above ten,"); if x > 20: print("and also above 20!") else: print("but not above 20."). [S1]
  • Three-level nesting: score → attendance → submitted, each gating the next. [S1]
  • Equivalent forms: if temperature > 20: if is_sunny: ...if temperature > 20 and is_sunny: .... [S1]

⚖️ 모순 및 업데이트 (Contradictions & updates)

소스에서 모순되는 정보는 발견되지 않음.

🛠️ 적용 사례 (Applied in summary)

현재 발견된 실제 적용 사례가 없습니다 — 로그인 검증(username→password→is_active)처럼 단계적으로 좁혀지는 조건 체크에 전형적으로 쓰인다. [S1]

💻 코드 패턴 (Code patterns)

Nested if for step-wise validation (Python):

username = "Emil"
password = "python123"
is_active = True
if username:
    if password:
        if is_active:
            print("Login successful")
        else:
            print("Account is not active")
    else:
        print("Password required")
else:
    print("Username required")

검증 상태 및 신뢰도

  • 상태: draft
  • 검증 단계: conceptual
  • 출처 신뢰도: B (W3Schools — widely used educational reference, not a primary standards body)
  • 신뢰 점수: 0.90
  • 중복 검사 결과: 신규 생성 (New discovery)

🔗 지식 그래프 (Knowledge Graph)

📚 출처 (Sources)

📝 변경 이력 (Change history)

  • 2026-07-04: Initial draft synthesized from the W3Schools "Python Nested If" page (Astra wiki-curation, P-Reinforce v3.1 format).