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id, title, category, status, verification_status, canonical_id, aliases, duplicate_of, source_trust_level, confidence_score, created_at, updated_at, review_reason, merge_history, tags, raw_sources, applied_in, github_commit
| id | title | category | status | verification_status | canonical_id | aliases | duplicate_of | source_trust_level | confidence_score | created_at | updated_at | review_reason | merge_history | tags | raw_sources | applied_in | github_commit | |||||||||
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| cpp-function-structures | C++ Pass Structures to a Function | Programming_Language | draft | conceptual |
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B | 0.86 | 2026-07-04 | 2026-07-04 |
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CPP Pass Structures to a Function
🎯 한 줄 통찰 (One-line insight)
Passing a struct WITHOUT & gives the function a full COPY — mutating it inside the function leaves the caller's original untouched — while passing it WITH & gives the function the ORIGINAL, letting c.year++; permanently increment the caller's struct field, meaning the exact same & reference syntax from the Pass By Reference chapter extends naturally to entire structs, not just primitive types like int/string. [S1]
🧠 핵심 개념 (Core concepts)
- Pass by value (default) —
void myFunction(Car c)gives the function a COPY of the struct; modifyingcinside the function does NOT affect the caller's original. [S1] - Pass by reference (
Car &c) — gives the function the ORIGINAL struct; modifications inside the function DO persist in the caller. [S1] - When to use reference — to let the function change the struct's data, OR to avoid copying large structures (performance). [S1]
📖 세부 내용 (Details)
- Pass by value — original unaffected:
struct Car { string brand; int year; }; void myFunction(Car c) { cout << "Brand: " << c.brand << ", Year: " << c.year << "\n"; } Car myCar = {"Toyota", 2020}; myFunction(myCar); // myCar unchanged after this call. [S1] - Pass by reference — original mutated:
void updateYear(Car &c) { c.year++; } Car myCar = {"Toyota", 2020}; updateYear(myCar); cout << myCar.year; // 2021 — the original was incremented. [S1]
⚖️ 모순 및 업데이트 (Contradictions & updates)
- 값 전달과 참조 전달의 결과 차이: & 없이 구조체를 전달하면 함수는 복사본을 받아 원본이 바뀌지 않지만, &를 붙이면 원본 자체를 받아 함수 안의 변경이 그대로 유지된다는 점이 year++ 예제로 직접 대비되어 증명됨. [S1]
🛠️ 적용 사례 (Applied in summary)
자동차 구조체의 연식(year)을 참조로 전달받아 함수 안에서 1씩 증가시키고 그 변경이 원본에 반영되는 updateYear() 예제가 원문에서 직접 실전 활용 사례로 제시됨. [S1]
💻 코드 패턴 (Code patterns)
Passing a struct by reference so the function can permanently modify it (C++):
struct Car {
string brand;
int year;
};
void updateYear(Car &c) {
c.year++;
}
int main() {
Car myCar = {"Toyota", 2020};
updateYear(myCar);
cout << "The " << myCar.brand << " is now from year " << myCar.year << "."; // 2021
return 0;
}
✅ 검증 상태 및 신뢰도
- 상태: draft
- 검증 단계: conceptual
- 출처 신뢰도: B (W3Schools — widely used educational reference, not a primary standards body)
- 신뢰 점수: 0.86
- 중복 검사 결과: 신규 생성 (New discovery)
🔗 지식 그래프 (Knowledge Graph)
- 상위/루트: C++ Tutorial
- 관련 개념: CPP Function Reference, CPP Functions Recursion, CPP Structs
- 참조 맥락: 구조체를 함수로 전달 — 재귀(Functions Recursion) 챕터로 이어짐.
📚 출처 (Sources)
- [S1] W3Schools — C++ Pass Structures to a Function — https://www.w3schools.com/cpp/cpp_function_structures.asp
📝 변경 이력 (Change history)
- 2026-07-04: Initial draft synthesized from the W3Schools "C++ Pass Structures to a Function" page (Astra wiki-curation, P-Reinforce v3.1 format).