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id title category status verification_status canonical_id aliases duplicate_of source_trust_level confidence_score created_at updated_at review_reason merge_history tags raw_sources applied_in github_commit
cpp-function-structures C++ Pass Structures to a Function Programming_Language draft conceptual
pass by value struct
pass by reference struct
C++ 구조체를 함수로 전달
B 0.86 2026-07-04 2026-07-04
cpp
programming-language
w3schools
functions
structs
https://www.w3schools.com/cpp/cpp_function_structures.asp

CPP Pass Structures to a Function

🎯 한 줄 통찰 (One-line insight)

Passing a struct WITHOUT & gives the function a full COPY — mutating it inside the function leaves the caller's original untouched — while passing it WITH & gives the function the ORIGINAL, letting c.year++; permanently increment the caller's struct field, meaning the exact same & reference syntax from the Pass By Reference chapter extends naturally to entire structs, not just primitive types like int/string. [S1]

🧠 핵심 개념 (Core concepts)

  • Pass by value (default)void myFunction(Car c) gives the function a COPY of the struct; modifying c inside the function does NOT affect the caller's original. [S1]
  • Pass by reference (Car &c) — gives the function the ORIGINAL struct; modifications inside the function DO persist in the caller. [S1]
  • When to use reference — to let the function change the struct's data, OR to avoid copying large structures (performance). [S1]

📖 세부 내용 (Details)

  • Pass by value — original unaffected: struct Car { string brand; int year; }; void myFunction(Car c) { cout << "Brand: " << c.brand << ", Year: " << c.year << "\n"; } Car myCar = {"Toyota", 2020}; myFunction(myCar); // myCar unchanged after this call. [S1]
  • Pass by reference — original mutated: void updateYear(Car &c) { c.year++; } Car myCar = {"Toyota", 2020}; updateYear(myCar); cout << myCar.year; // 2021 — the original was incremented. [S1]

⚖️ 모순 및 업데이트 (Contradictions & updates)

  • 값 전달과 참조 전달의 결과 차이: & 없이 구조체를 전달하면 함수는 복사본을 받아 원본이 바뀌지 않지만, &를 붙이면 원본 자체를 받아 함수 안의 변경이 그대로 유지된다는 점이 year++ 예제로 직접 대비되어 증명됨. [S1]

🛠️ 적용 사례 (Applied in summary)

자동차 구조체의 연식(year)을 참조로 전달받아 함수 안에서 1씩 증가시키고 그 변경이 원본에 반영되는 updateYear() 예제가 원문에서 직접 실전 활용 사례로 제시됨. [S1]

💻 코드 패턴 (Code patterns)

Passing a struct by reference so the function can permanently modify it (C++):

struct Car {
  string brand;
  int year;
};
void updateYear(Car &c) {
  c.year++;
}
int main() {
  Car myCar = {"Toyota", 2020};
  updateYear(myCar);
  cout << "The " << myCar.brand << " is now from year " << myCar.year << "."; // 2021
  return 0;
}

검증 상태 및 신뢰도

  • 상태: draft
  • 검증 단계: conceptual
  • 출처 신뢰도: B (W3Schools — widely used educational reference, not a primary standards body)
  • 신뢰 점수: 0.86
  • 중복 검사 결과: 신규 생성 (New discovery)

🔗 지식 그래프 (Knowledge Graph)

📚 출처 (Sources)

📝 변경 이력 (Change history)

  • 2026-07-04: Initial draft synthesized from the W3Schools "C++ Pass Structures to a Function" page (Astra wiki-curation, P-Reinforce v3.1 format).