refactor(topics): 멀티 에이전트용 지식 재편 — _Common(공통 기본기) + Domain_* 구조

에이전트 8종(대화형/프로그래머 C·S/디자이너/설계자/기획자/QA/PD/PM)에게
[공통 기본 능력 + 롤별 Specialty] 2층으로 지식을 주입하기 위한 재분류.
문서 내용·포맷은 무수정, 폴더 이동만 (6,372개 문서 수 보존 확인).

- Topic_Programming → Domain_Programming (내부 구조 보존)
- Topic_Graphic → Domain_Design
- Topic_Business → Domain_Product
- Topic_General → Domain_General
- _Common 신설: Math(구 Topic_Math_Specialty), Reasoning(구 General/From_Thinking & Reasoning),
  Reasoning_Creativity(구 General/From_창의성), Communication(Poetic_Blog_Writing + From_writing)
- 타 도메인의 From_* 폴더는 유지 (출처 표기일 뿐, 이미 도메인에 맞게 분류된 문서)
- 빈 폴더 정리 (memory/procedures)
- 에이전트→폴더 매핑은 workspace의 .astra/agent-knowledge-map.json (9개 에이전트)

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
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Antigravity Agent
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---
id: sql-count
title: "SQL Count"
category: "Database"
status: "draft"
verification_status: "conceptual"
canonical_id: ""
aliases: ["SQL COUNT() Function", "COUNT function", "SQL 개수 세기"]
duplicate_of: ""
source_trust_level: "B"
confidence_score: 0.9
created_at: 2026-07-04
updated_at: 2026-07-04
review_reason: ""
merge_history: []
tags: ["sql", "database", "w3schools", "count", "aggregate"]
raw_sources: ["https://www.w3schools.com/sql/sql_count.asp"]
applied_in: []
github_commit: ""
---
# [[SQL Count]]
## 🎯 한 줄 통찰 (One-line insight)
COUNT() behaves differently depending on its argument — `COUNT(*)` counts all rows including NULLs, `COUNT(column)` counts non-null values, and `COUNT(DISTINCT column)` counts unique non-null values. [S1]
## 🧠 핵심 개념 (Core concepts)
- **COUNT() function** — returns the number of rows matching a specified criterion. [S1]
- **Syntax** — `SELECT COUNT([DISTINCT] column_name | *) FROM table_name WHERE condition;`. [S1]
- **`COUNT(*)`** — counts the total number of rows, including NULL values. [S1]
- **`COUNT(column_name)`** — counts only non-null values in that column. [S1]
- **`COUNT(DISTINCT column_name)`** — counts only unique, non-null values. [S1]
## 🧩 추출된 패턴 (Extracted patterns)
- **Argument choice changes semantics** — the three COUNT variants answer three different questions (total rows / filled-in rows / unique values), so picking the right one matters for correctness, not just style. [S1]
## 📖 세부 내용 (Details)
- Total row count: `SELECT COUNT(*) FROM Products;`. [S1]
- Non-null count for a column: `SELECT COUNT(ProductName) FROM Products;`. [S1]
- Unique non-null count: `SELECT COUNT(DISTINCT Price) FROM Products;`. [S1]
- With WHERE: `SELECT COUNT(ProductID) FROM Products WHERE Price > 20;`. [S1]
- With alias: `SELECT COUNT(*) AS [Number of records] FROM Products;`. [S1]
- With GROUP BY: `SELECT COUNT(*) AS [Number of records], CategoryID FROM Products GROUP BY CategoryID;`. [S1]
## ⚖️ 모순 및 업데이트 (Contradictions & updates)
소스에서 모순되는 정보는 발견되지 않음.
## 🛠️ 적용 사례 (Applied in summary)
현재 발견된 실제 적용 사례가 없습니다 — SELECT DISTINCT 챕터에서 이미 소개된 `COUNT(DISTINCT ...)` 패턴이 여기서 정식으로 다뤄진다. [S1]
## 💻 코드 패턴 (Code patterns)
Three COUNT variants (SQL):
```sql
SELECT COUNT(*) FROM Products; -- all rows, incl. NULLs
SELECT COUNT(ProductName) FROM Products; -- non-null values only
SELECT COUNT(DISTINCT Price) FROM Products; -- unique non-null values
```
## ✅ 검증 상태 및 신뢰도
- **상태:** draft
- **검증 단계:** conceptual
- **출처 신뢰도:** B (W3Schools — widely used educational reference, not a primary standards body)
- **신뢰 점수:** 0.90
- **중복 검사 결과:** 신규 생성 (New discovery)
## 🔗 지식 그래프 (Knowledge Graph)
- **상위/루트:** [[SQL Tutorial]]
- **관련 개념:** [[SQL Aggregate Functions]], [[SQL Select Distinct]], [[SQL Group By]]
- **참조 맥락:** 행 개수를 세는 모든 리포트의 기본 함수 — DISTINCT와 결합해 고유값 개수도 셀 수 있다.
## 📚 출처 (Sources)
- [S1] W3Schools — SQL COUNT() Function — https://www.w3schools.com/sql/sql_count.asp
## 📝 변경 이력 (Change history)
- 2026-07-04: Initial draft synthesized from the W3Schools "SQL COUNT() Function" page (Astra wiki-curation, P-Reinforce v3.1 format).